In ΔMNO, the measure of ∠O=90°, the measure of ∠N=48°, and NO = 73 feet. Find the length of MN to the nearest tenth of a foot.

109.1 feet

Step-by-step explanation:

What function uses the ADJACENT and the HYPOTENUSE?

\text{SOH-CAH-TOA}

SOH-CAH-TOA

\cos N = \frac{\text{adjacent}}{\text{hypotenuse}}=\frac{73}{x}

cosN=

hypotenuse

adjacent

​

=

x

73

​

\cos 48=\frac{73}{x}

cos48=

x

73

​

x\cos 48=73

xcos48=73

Cross multiply.

\frac{x\cos 48}{\cos 48}=\frac{73}{\cos 48}

cos48

xcos48

​

=

cos48

73

​

Divide each side by cos 48.

x=\frac{73}{\cos 48}=109.0968\approx 109.1\text{ feet}

x=

cos48

73

​

=109.0968≈109.1 feet

Type into calculator and roundto the nearest tenth of a foot.

answer:

c. the third graph