10x^5+5x^2−15

5x^2(2x^3+x−3)
10(x^5+5x^2−15)
5(2x^5+5x^2−15)
5(2x^5+x^2−3)

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Step-by-step explanation:

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Step-by-step explanation:

the answer to your question is minor arc.

1) the property is   ixi = a ⇔x = a   o x = -a

4(x-5)+3= 15⇒4x-20+3 = 15⇒4x-17= 15⇒4x = 15+17⇒4x = 32⇒x =32/4= 8

4(x-5) +3= -15⇒4x-20 +3 = -15⇒4x-17= -15⇒4x =-15+17⇒4x = 2⇒x =2/4= 1/2

the values are x =8 and x = 0,5