This is the previous problem: A rabbit started at point 0 and made 3 jumps a jump of 4 units then a jump of 2 units and then a jump of 1 unit we do not know the direction of either jump where on the line could the rabbit be. This is my question: next time, the rabbit from the previous problem started at 10. Where on the number line can he be after the same three jumps?

Q1: The rabbit could be at eight different numbers of the number line: -7, - 5, - 3, - 1, 1, 3, 5, and 7.

Q2: 13

Step-by-step explanation:

Q1: Let's simulate each of the jumps of the rabbit in all the possible directions, as follows:

Option 1: - 4 - 2 - 1 = -7

Option 2: - 4 - 2 + 1 = -5

Option 3: - 4 + 2 - 1 = - 3

Option 4: - 4 + 2 + 1 = - 1

Option 5:  4 - 2 - 1 = 1

Option 6: 4 - 2 + 1 = 3

Option 7: 4 + 2 - 1 = 5

Option 8: 4 + 2 + 1 = 7

Q2: If the rabbit started at 10 you would add 3 to 10 and get 13.

if x = 1, then the answer is 3.5

first, you divide the triangle in two, tô form a retangle triangle. after, using pythagoream theorem:

18^2 = 14^2 + (x/2)^2

(x^2/4) + 196 = 324

x^2/4 = 324 - 196

x^2/4 = 128

x^2 = 512

x = √512

x = √2^9

x = 16√2 cm

i hope i you.