The first one is done and the options for number four are:
w(2w+12)=160
2w^2+12w-260=0
...
Mathematics, 03.03.2021 20:40 sovprints
The first one is done and the options for number four are:
w(2w+12)=160
2w^2+12w-260=0
2w^2+12w=260
w^2+6w-130=0
Answers: 3
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