If 8^y = 16^x + 2 what is the value of Y

y= -8

Step-by-step explanation:

8^y = 16^(y+2)

//to solve make the base equal, both 8 and 16 are powers of (2

(2^3)^y = (2^4)^(y+2)

//simplify, remember when doing this multiply the powers

2^3y = 2^(4y+8)

// now we can just make the 2 powers equal

3y = 4y+8

0=y+8

y= -8

check:

8^(-8) = 16^(-6)

2^(-24) = 2^(-24)

80%

step-by-step explanation:

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