A triangle has sides that are 3, 7, and squareroot 57. Is the triangle a right triangle?

my answer is no because for a right angle triangle the sum of the squares of the other two sides is equal to the square of the longest side

3²+7²=9+49=58

(√57)²=57

57≠58 it's not a right angle triangle

assume the sides to be a,b and c

a=3 b=7 c=√57

by Pythagoras theorem

a²+b²=c²

3²+7²=√57²

but 58≠57

hope it's clear