Write the ratios for sin x, cos x and tan x

sin(x)= / 12, cos(x)=5/12, tan= / 5

Step-by-step explanation:

segment YZ is length a, we need to find a

segment XZ is length 5

segment XY is length 12

XYZ is a right triangle, so a^2 + b^2 = z^2, so

a^2 + 5^2 = 12^2, simplify

a^2 + 25 = 144, subtract 25

a^2 = 119

a =

then we can determine all the trig ratios

soh - cah - toa

sin = opp/hyp, cos=adj/hyp, tan=opp/adj

sin(x)= / 12, cos(x)=5/12, tan= / 5

10a^3+277a^2-132a-792

step-by-step explanation:

(2a+11)(5a-12)(foil)

=10a^2-24a+55a-132 =10a^2+31a-132

(10a^2+31a-132)(a+6)

=10a^3+60a^2+31a^2+186a^2-132a-792 =10a^3+277a^2-132a-792

i hope this is what you are looking for : )

idk man good luck man