Wire mesh enclosures for two batting cages are to be built side by side at a school. If each cage needs 240 m3 of space, what is the minimum amount of wire mesh needed, where ? (Wire mesh is not needed on the bottom of the cage.)

3: 2

step-by-step explanation:

shorter piece is 2: 3, so just reverse it, and you get 3: 2

2

step-by-step explanation:

answer: cos [   arcsin (3/5) - arccos (1/2) ] =

step-by-step explanation: × = 3/5 = 0.6--> x = 36.87 and x = 180 - 36.87 = 143.13 deg

cos y = 1/2 --> y = +- 60 deg a. cos (x - y) = cos (143.13 - 60) = cos 83,13  

=

0.12

b. cos (36.87 - 60) = cos (-23.23) = 0.92

5 quiero

6 vamos

7 puedan

8 quiero

9pedemos

10 dorme

step-by-step explanation: