How much force is needed to stop a 1,400 kg truck pulling up to a stop light if the truck took 4 seconds to stop and was moving at 36 m/s? If you know the answer please include the equation, it would really help me out, thank you! This is not math is is science btw.

Hi there!

Recall that the equation to calculate force is:

F = m · a where m = mass, a = acceleration, and F = net force.

Since we are given the velocity, and time needed to stop, we can calculate the acceleration using the following kinematic equation:

vf = vi + at

The initial velocity is 36 m/s and the final velocity is 0 m/s, therefore:

0 = 36 + at

Move 36 to the other side and plug in the given time:

-36 = 4a

Divide both sides by -4 to find a:

-36/4 = a

a = -9 m/s².

Since the acceleration is -9 m/s² and the mass is 1400 kg, use the above force equation to solve:

F = -9 × 1400 = -12600 N. (negative refers to the force working in the opposite direction of the car's travel. If simply needing the magnitude of the force, it would be 12600 N)

300

step-by-step explanation:

28-600w < 300

28-600w > 300

600-28w < 300

600-28w > 300