Anyone can help please

I haven't done this in a while but I'm pretty sure the answer is

D; The outlier

D - outlier

Step-by-step explanation:

It can’t be A - the spread would the minimum and maximum.

‘Can’t be B - the mean in the overall average, which would probably be a bit higher than 13

Can’t be C - the median is the “middle” number when ordered smallest to largest. It would be 13 in this example

24 is an odd number compared to the rest. It seems like it might be an error in the data, because it is so different than all the rest - hence it is the outlier.

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12

only 10/60 isn't equivalent

hope this : )