Part A: find the measure of x and y Part B: choose the correct degree measure for arc JKL

x = 7

y = 4

Arc JKL = 262°

Step-by-step explanation:

Find the diagram attached

Using the theorem;

Sum of opposite angle of the quadrilateral is 180°

7x+131 = 180

7x = 180-131

7x = 49°

x = 49/7

x = 7

Similarly;

11x+y+99 = 180°

11(7)+y+99 = 180°

77+99+y = 180

176+y = 180

y = 180-176

y = 4

arc JKL is the obtuse angle at the centre

Arc JKL = 360-(angle at the centre)

Angle at the centre is twice angle at the circumference.

Angle at the centre = 2(7x)

Angle at the centre = 2(49)

Angle at the centre = 98°

Arc JKL = 360-98

Arc JKL = 262°

can you make your screen more see able?

then i might be able to .

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.