For what value of the constant c
is the function
f
continuous on
(
−
∞
,
∞
)
where
f
(
b
)
=
{
c
b
+
9
if
b
≤
3
c
(
b
)
2
−
9
if
b
>
3

9514 1404 393

  c = 3

Step-by-step explanation:

In order for the function to be continuous at b=3, the left and right limits must be the same. In short, we must have ...

  c(3) +9 = c(3²) -9

  18 = 6c . . . . . . . . add 9-3c to both sides

  3 = c . . . . . . . . . . divide by 6

Function f is continuous when c=3.

3/4 ÷ 3/4

step-by-step explanation:

basically divide any proper fraction with itself to fit the criteria.

so if we are using 3/4, then:

3/4 ÷ 3/4 = 1

so 1 is the quotient.

and the numerators for both these fractions is 3.   and if we divide the numerators:

3 ÷ 3 = 1

we see that quotient is equal to our original quotient as well.

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3