Two cards are dealt, one at a time, from a standard 52-card deck. What is the probability that the 2 cards are spades, if sampled (a) without replacement; (b) with replacement? (a) without replacement: 0.0588; (b) with replacement: 0.0625
(a) without replacement: 0.0577; (b) with replacement: 0.0637
(a) without replacement: 0.0588; (b) with replacement: 0.0637
(a) without replacement: 0.5557; (b) with replacement: 0.0625

abde or 1,2,4, 5 is the answer

step-by-step explanation:

how am i supposed to answer

step-by-step explanation:

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18

32/80  

91/140

the last one 54 doesn't go into 45. 54/100 ?

step-by-step explanation: