Arectangular room has an area of 425 square feet. one dimension is 8 feet more than the other. find both dimensions of the room.

Area is calculated using length time width.

If we let the shorter dimension equal x, we can write the equation as x(x+8)=425

Expand and rearrange to get a quadratic, then solve

x^2+8x-425=0

(x+25)(x-17)=0

x=-25 or x=17