A 500-foot cable is attached to the top of a tower and is stretched tight to a point that is 350 feet away from the base of the tower. What is the angle of depression formed by the cable? A. 34.9° B. 35.3° C. 44.4° D. 45.6°

p ÷ r = tan(x)

step-by-step explanation:

given that there is a figure below shows a right triangle: a right triangle is shown with hypotenuse equal to q units and the length of the legs equal to p units and r units.

graph is missing so i will create the graph as per given information.

the angle between the legs having lengths p units and q units is y degrees. the angle between the legs having lengths r units and q units is x degrees.

now we need to find about what is p ÷ r equal to.

so we can use trigonometric ratio tan(x)=[altitude]/[base] to find the value of p ÷ r, because p is the altitude and r is the base.

p ÷ r=tan(x)

hence final answer is p ÷ r=tan(x).

correct answer is b. 27/8

step-by-step explanation:

the answer is:

mean: 6

mad: 2.14