WILL GIVE 20 PTS! An eastbound car is going 12 miles per hour faster than a westbound car. the cars are 208 miles apart 2 hours after passing each other on a highway. what is the speed, in miles per hour, of the eastbound car?
A)46
b)52
c)58
d)49
e)55​

Draw a diagram to illustrate the problem as shown below.

Let v = speed of the westbound car, mph

Because the eastbound car travels 4 mph faster than the westbound car, its speed is (v+4) mph.

After 2 hours,

the westbound car travels 2v miles west, and the eastbound car travels 2(v+4) miles east.

Because they become separated by 208 miles, therefore

2v + 2(v+4) = 208

4v + 8 = 208

4v = 200

v = 50 mph

The westbound car travels at 50 mph.

The eastbound car travels at v+4 = 52 mph

The eastbound car travels at 49

there is your answer :)

i think its D good luck!

Step-by-step explanation:

1. sometimes

2. never true

3. sometimes

step-by-step explanation:

these are pretty self explanatory if you know what supp right and com angles are

step-by-step explanation:

this can be solved first with pythagorean theorem, which tells us to square both legs of the triangle and sum it. this will be equal to the square of the hypotenuse.

the hypotenuse is the side "opposite" the 90 degree angle, which is x.

so we can write using pythagorean theorem,

simplifying:

to further simplify this radical, we need to use the property  

thus