(points on a circle) PLEASE HELP THIS IS DUE TONIGHT A circle is centered at C(0,0)C(0,0)C, left parenthesis, 0, comma, 0, right parenthesis. The point M(0,\sqrt{38})M(0,38 )M, left parenthesis, 0, comma, square root of, 38, end square root, right parenthesis is on the circle.

Where does the point N(-5,-3)N(−5,−3)N, left parenthesis, minus, 5, comma, minus, 3, right parenthesis lie?

Inside the circle, a distance of from the center of the circle.

Step-by-step explanation:

Center of circle is at (0,0)

One point of the circle is at (0,)

Since the only known point is in the y-axis, the radius of the circle must be .

= 6.164

So the point (-5,-3) is still inside the circle as the distance from point (-5,-3) to the center of the circle is or which is less than the radius of the circle.

for this case we have by definition, if two lines are perpendicular, then the product of their slopes is -1.

then, given the following line:

so,

we are looking for m_ {2}:

then, the line is given by:

we find "b" replacing the given point:

finally, the equation is:

option c

step-by-step explanation: