D, E, and F are on sides BC, AC, and AB, respectively, of Triangle ABC such that DE║AB, DF║AC, and BC║EF. Prove that D, E, and F are the midpoints of the sides of Triangle ABC. Please help I desperately need help to understand this. Thank you! Whoever can help me I will give the Brainliest! Just pls help T^T

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2

asdfghkl

step-by-step explanation:

asdfghkl