A triangle has two sides measuring 10 inches and 16 inches. The angle opposite the 16-inch side measures 68.9°. Solve the triangle. Round answers to the nearest tenth of a degree. Do not round intermediate values.

measure of two unknown angles are 35.7° and 75.4°

measure of one unknown side is 16.6 inches

Step-by-step explanation:

i used law of sines to find the angle opposite 10 inch side

sin 68.9/16 = sinФ/10

Ф = 35.7°

then is added 35.7 and 68.9 and subtracted the sum from 180° to get the measure of the third angle, 75.4°

i used law of sines again to find the measure of the third side

sin 68.9/16 = sin 75.4/x

x = 16.59

let's solve your equation step-by-step.

4x+2=2x+12

step 1: subtract 2x from both sides.

4x+2−2x=2x+12−2x

2x+2=12

step 2: subtract 2 from both sides.

2x+2−2=12−2

2x=10

step 3: divide both sides by 2.

2x

2

=

10

2

x=5

step-by-step explanation:

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18