find the probility that number chose at random from tha integers between 5 and 16 inclusive is a multiple of 3 or a multiple of 2​

Numbers between 5 and 16 are:-

6, 7, 8, 9, 10, 11, 12, 13, 14 , 15 and 16.

Therefore, total number of outcomes =11

Numbers inclusive between 5 and 16 which are divisible by 2 or 3 are-

6 , 8, 9 ,10 ,12, 14 and 15.

Number of favourable outcomes = 7

Therefore, probability of getting a number which is either a multiple of 2 or 3 is:

p(e) = \frac{7}{11}p(e)=

11

7

HENCE, THE REQUIRED PROBABILITY IS = 7 / 11.

IF THIS IS RIGHT PLZ AKE ME BRAINLIANLIEST

Step-by-step explanation:

P(3)= All multiple of 3/Total outcome=4/11

P(2)= All the multiple of 2/Total outcome = 7/11

:):):):)

c

step-by-step explanation:

it would be see because your formula is f(x)=6x, so 6 times 1 is 6 and you go on and the best answer is c.