Write down an expression for the nth term of the following sequence

7, 11, 15, 19, ...

= 4n + 3

Step-by-step explanation:

There is a common difference d between consecutive terms , that is

d = 11 - 7 = 15 - 11 = 19 - 15 = 4

This indicates the sequence is arithmetic with n th term

= a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 7 and d = 4 , then

= 7 + 4(n - 1) = 7 + 4n - 4 = 4n + 3

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐