Find the zeros of the function.
9x^2-36=0
I've gotten half way right up to
9(x^2-4)=0​

x = ±2

Step-by-step explanation:

9x^2-36=0

Using the square root property

9x^2 = 36

Divide each side by 9

x^2 = 4

Take the square root of each side

sqrt(x^2) = sqrt(4)

x = ±2

the answer is d. (1.2, -4.7) on edgn

hope this !