[ ASAP ! ]
Will give brainiest to the first correct answer
<3

D

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

Here (h, k ) = (- 3, 4 ) and r = 3 , then

(x - (- 3))² + (y - 4)² = 3² , that is

(x + 3)² + (y - 4)² = 9 → D

Step-by-step explanation:

{x-(-3/4)}^2=3^2

(x+3/4)^2=9

{(4x+3)/4}^2=9

(4x+3)^2/16=9

(4x+3)^2=9*16

16x^2+2*4x*3+3^2=144

16x^2+24x+9=144

16x^2+24x+9-144=0

16x^2+24x-135=0

We are given a circle which is centered at the point (-3,4) and has a radius of length 3.

We have to find the equation of the circle.

The equation of circle centered at (a,b) and radius r is-

   Here a=-3 , b=4 and r=3

Hence, equation of circle is:

  (x+3)^2 + (y-4)^2 = 3^2

  (x+3)^2 + (y-4)^2 =9