A bag contains 4 blue and 5 red counters. Two counters are chosen at random without replacement. What is the probability that the counters are both red?

P(both are red) = 5/18

Step-by-step explanation:

total counters = 9

red counters = 5

P(both red) = P(R1) n P(R2)

5/9 * 4/8 =5/18

5/9 because the red counters are 5 and the total number of counters are 9.

I multiplied by 4/8 because, after selecting the first red counter without replacement, the remaining is 4 and the total decreases to 8.

answer: this doesnt make any sense especially the photo.

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