three consecutive odd integers are such that three times the smallest is 9 more than twice the largest find the three numbers​

https://www.wyzant.com/resources/answers/732264/three-consecutive-odd-integers-are-such-that-3-times-the-smallest-is-9-more

Step-by-step explanation:

On this link your question has been given solved.

Hope this helps you. Do mark me as brainliest.

17, 19, 21

Step-by-step explanation:

let the 3 consecutive odd numbers be n, n + 2 and n + 4 , then

3n = 2(n + 4) + 9 ( 3 times smallest is 9 more than twice the largest )

3n = 2n + 8 + 9

3n = 2n + 17 ( subtract 2n from both sides )

n = 17

n + 2 = 17 + 2 = 19

n + 4 = 17 + 4 = 21

The 3 numbers are 17, 19, 21

the answer is simply just 6n add the two together as they have an n

shift 4 units up, and 1 unit left.

it will translate f(x) = 3^x to g(x) = 3^(x+1) + 4