Mr. Sandeep Kalra is a social worker. He always works for the welfare of his welfare of his village. In his village, there was no school building. Sandeep gave a rectangular plot of land for the school building. the length and breadth of the plot are 150m and 100m. the villagers with the help of Mr. Sandeep made the school in the shape of a cuboid whose dimensions are 50m*40m*15m. they also fenced the plot at rs 50 per m. i) Find the area of the plot
ii)Find the base area of the school.
iii)what is the volume of the building?
iv)find the perimeter of the plot.
v)what is the cost of the fencing the plot

i) The area of the plot of land is 15,000 m²

ii) The base area of the school is 2,000 m²

iii) The volume of the school building is 30,000 m³

iv) The perimeter of the plot of land is 500 m

v) The cost of fencing the plot of land is Rs 2,500

Step-by-step explanation:

The parameters of the land, the school building and the cost of fencing are;

The length of the land, l = 150 m

The breadth of the land, b = 100 m

The dimensions of the school = 50 m × 40 m × 15 m

The cost of fencing the plot per meter = Rs 50 per meter

i) The area of the plot of land, A = Length × Breadth

∴ A = 150 m × 100 m = 15,000 m²

The area of the plot of land, A = 15,000 m²

ii) Taking the height of the school, h = 15 m, the length of the school building, = 50 m, and the breadth of the school building, = 40 m, the base area of the school, , is given as follows;

= ×

∴ = 50 m × 40 m = 2,000 m²

iii) The volume of the school building, V = h ×   ×

∴ V = 15 m × 50 m × 40 m = 30,000 m³

iv) The perimeter of the plot of land, P = 2 × l + 2 × b

∴ P = 2 × 150 m + 2 × 100 m = 500 m

The perimeter of the plot of land, P = 500 m

v) The cost of fencing the plot of land, C = P × (The cost of fencing the plot per meter )

∴ C = 500 m × Rs 50/m = Rs 2,500

The cost of fencing the plot of land, C = Rs 2,500

d

step-by-step explanation:

by observation, we can see that the the graph is simply the graph of y = |x| that has been shifted 4 units downwards and 3 units to the left.

we can recognize in choice d :

y = | x + 3 |   - 4 (rewriting in general form)

y = | x - (- 3) |   - 4

the "-4 " term means   that the graph has been shifted by 4 units in the negative y direction

the "-3 " term means   that the graph has been shifted by 3 units in the negative x direction

this matches our observation of the graph described above.

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?