What is the slope of the line that passes through the points (-2, -11) and (-9, 17)?

rise/run

17--11/-9--2

=28/-7

=-4

Done!

Step-by-step explanation:

let (x1 , y1)= ( -2 , - 11)

(x2, y2 ) = ( - 9 , 17 )

slope (m )

= (y2 - y1 )/ (x2 - x1)

=( 17 + 11 ) / ( - 9 + 2)

= 28 / - 7

= -4

hope it will help :)

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

d

step-by-step explanation: