. You invest £4000 in a fund which earns 11% compound return per year. How much would the fund be worth after 10 years, given that you removed half of the balance after 5 years?

$5,678.85

Step-by-step explanation:

First find out how much the fund was worth after 5 years.

Compound interest formula:

= Investment * (1 + rate) ^ years

= 4,000 * ( 1 + 11%)⁵

= £6,740.23

Half was removed:

= 6,740.23/2

= £3,370.12

Then compound this for the remaining 5 years:

= 3,370.12 * (1 + 11%)⁵

= $5,678.85

idk but i found this "the graph of y = f(x-2) is the graph of y = f(x) translated two units rightward.  

so, since the point (9,2) lies on the graph of y = f(x), the point (11,2) lies on the graph of y = f(x-2)."

step-by-step explanation:

link is

you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)