A quantity with an initial value of 7800 decays continuously at a rate of 0.1% per hour. What is the value of the quantity after 1.25 days, to the nearest hundredth? please help

7569.36

Step-by-step explanation:

Given that a quantity with an initial value of 7800 decays continuously at a rate of 0.1% per hour. What is the value of the quantity after 1.25 days, 

First convert 1.25 days to hours

1.25 × 24 = 30 hours

Using exponential equation

N = No ( 1 - R% )^t

Where N = new value of the quantity

No = initial value

R = rate

t = time

N = 7800 ( 1 - 0.001 )^30

N = 7800 ( 0.999 )^30

N = 7800 × 0.97043

N = 7569.36154

N = 7569.36 to the nearest hundredth.

Therefore, the value of the quantity after 1.25 days is 7569.36

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

2160ft3

step-by-step explanation: