An object is traveling at a steady speed of 8 2/3 miles per hour. How long will it take the object to travel to 5 1/5 miles If the object reduces its speed by `\frac{1}{2}`, what is its speed? If the object reduces its speed by 30%, what is its speed after the reduction?

3/5 hour

4 1/3 miles per hour

6 1/15 miles per hour

Step-by-step explanation:

Given that the object is travelling at a steady speed of 8 2/3 miles per hour and covers  5 1/5 miles

Recall that distance  = speed * time

hence

5 1/5 miles =  8 2/3 miles per hour * time t

26/5 = 26/3 * t

Multiply both sides by 3/26

26/5 * 3/26 = t

t = 3/5 hour

If the object reduces its speed by 1/2, the new speed

= 1/2 * 8 2/3 miles per hour

= 1/2 * 26/3

= 13/3 miles per hour

= 4 1/3 miles per hour

If the object reduces its speed by 30%, the new speed

= 8 2/3 miles per hour - 30% * 8 2/3 miles per hour

= 0.7 * 8 2/3 miles per hour

= 7/10 * 26/3

= 91/15

= 6 1/15 miles per hour

water molecules will move from the side of higher water concentration to the side of lower concentration until both solutions are isotonic. at this point, equilibrium is reached. in an isotonic solution, the flow of water in and out of the cell is happening at the same rate.

hope this < 3