The perimeter of a rectangular field is 628m. the length of the field exceeds its width by 6m. find the dimensions​

154m , 160m

Step-by-step explanation:

Let width of the rectangle = w

Length = w + 6

Perimeter of rectangle = 628 m

2( length + width ) = 628

2( w + 6 + w) = 628        {Combine like terms}

2*( 2w +6 ) = 628            {Distributive property}

2*2w + 2*6 = 628

4w + 12 = 628         {subtract 12 from both sides}

        4w = 628 - 12

        4w = 616       {Divide both sides by 4}

        w = 616/4

       w = 154 m

Length = w + 6 = 154 + 6 = 160 m

geometry: triangles

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call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

25.45584

hi there!

the answer will be d: 2