If 3(d+1)=4(d–2),
then what is the value of 5(d–2)?

9514 1404 393

  45

Step-by-step explanation:

Solving for d, we find ...

  3(d +1) = 4(d -2)

  3d +3 = 4d -8 . . . . . . eliminate parentheses

  11 = d  . . . . . . . . . . . .  subtract 3d-8

Then the value of 5(d-2) is ...

  5(11 -2) = 5(9) = 45

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The graphical solution gives both the value of "d" and the value of 4(d-2). To get 5(d-2), we only need to add d-2 to the value of 4(d-2).

  5(d-2) = (11 -2) +36 = 45

options a,b,c are the right answer.

step-by-step explanation:

a linear parent function is always represented as y = x

if we write this function in the form of y=mx+c

⇒

or  

now if we plot a graph we will find these characteristics:

1) y intercept of the graph is zero so its a straight line passing through origin.

2) as we can see in both the forms of function written, values of x and y may be either positive or negative for the positive slope means points on the graph are either in first quadrant or in third one.

3) it's slope is one.