Which linear function has a graph that includes all of the points in the table? х
у
-22
-3
-1
-12
o
-7
2
3
13
Of(x) = -5x - 7
Of(x) = 5x - 7
f(x) = 2x + 6
O f(x) = -23 + 6

B. f(x) = 5x - 7

Step-by-step explanation:

✔️Using the table of values given, find the slope (m) and y-intercept (b) of the line of the graph that represents the table, then write the function in slope-intercept form.

✔️Slope (m) using (0, -7) and (2, 3):

Slope (m) = ∆y/∆x

Slope (m) = (3 -(-7))/(2 - 0)

Slope (m) = 10/2

Slope (m) = 5

✔️ y-intercept (b):

b = -7, because where x = 0, y = -7, which is the point where the y-axis is intercepted by the line of the graph.

✔️Write the linear function in slope-intercept form by substituting m = 5 and b = -7 into f(x) = mx + b

Thus:

f(x) = 5x + (-7)

f(x) = 5x - 7

Therefore, the linear function that has a graph that includes all the points in the table would be f(x) = 5x - 7.

the answer is c just got it on ed

step-by-step explanation:

b. y = 4x - 2

step-by-step explanation:

to find a parallel equation to an equation, make sure both equations have the same slope but different y-intercepts.

y = 4x + 1

4 = slope

1 = y-intercept

y = 4x - 2

4 = slope

-2 = y-intercept

they both have the same slope but different y-intercepts, so, b. is the correct answer.

and to check your work, you can graph both equations. : )