A triangle with area 40 square inches has a height that is four less than six times the base. Find the base and height of the triangle

A = 1/2bh

Step-by-step explanation:

40 = (.5)(6x - 4)(x)

40 = (3x-2)(x)

40= 3x^2 - 2x

3x^2 -2x - 40 =0

3x^2 - 12x + 10x - 40 = 0

3x(x - 4) + 10(x -4) = 0

(3x + 10)(x - 4) = 0

x = {4 , - 10/3}

x = 4 , b = 20. h = 4

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

step-by-step explanation:

se a cavasery6