Help please! Function Notation

Given f(x)=8x−9

a. Find f(3y−1)=8(3y−1)−9=

b. If f(x)=−23, find the value of x.

Step-by-step explanation:

Given

f(x) = 8x - 9

Then

For a.

f(3y - 1 ) = 8(3y - 1 ) - 9

= 24y - 8 - 9

= 24y - 17

Now for b.

f(x) = - 23

or, 8x - 9 = - 23

8x = - 23 + 9

8x = - 14

x = - 14 / 8

x = - 7 / 4

Hope it will help :)

x^2 + 81

we can factor this using difference of square binomials.

rewrite the equation:

x^2 - (-81)

factor:

(a^2 - b^2) = (√a^2 + √b^2)(√a^2 - √b^2)

(x^2 - (-81) = (x + √-81)(x - √-81)

we can remove the - from under the radical by multiplying it by i.

(x^2 - (-81) = (x + i√81)(x - i√81)

(x^2 - (-81) = (x + 9i)(x - 9i)

we can check our answer by using foil:

x^2 - 9ix + 9ix - 81i^2

x^2 - 81^2

i^2 = -1

x^2 + 81

what do you mean

have a great day