The rectangle shown has a perimeter of 58 cm and the given area. Its length is 4 more than four times its width. The area of the rectangle is 120 cm2. Write and solve a system of equations to find the dimensions of the rectangle.

w=5

Step-by-step explanation:

58=l+l+w+w

l=4w+4

58=(4w+4)+(4x+4)+w+w

58=8w+8+w+w

58=10w+8

50=10w

5=w

w=5

l=4w+4

l=4(5)+4

l=20+4

l=24

check:

w=5, l=24,

5*24=120

our answer is correct

The length of the rectangle is 24cm and the width of the rectangle is 5cm.

Step-by-step explanation:

Length=4+4w

Perimeter=L+W+L+W

P=4+4w+w+4+4w+w

P=10w+8

Now that we have our equation we can solve it. Since the perimeter is 58cm, you can switch the letter P for 58.

58=10w+8

Then subtact 8 from both sides.

50=10w

Then divide both sides by 10.

5=w

Now we know that the width is 5cm, but we still have to solve for length.

L=4+4w

Trade the w for 5 because the width is 5cm.

L=4+4x5

L=4+20

L=24

The length is 24cm.

bru

step-by-step explanation:

the median here is 25. your lowest value is 14 and highest value is 48. to find the third quartile, find the medium number in between 25 and 48 which would be 42 i believe.