Choose the equation that could be used to find two consecutive integers whose sum is 69. (5 points)

select one:
a. n + (n + 2) = 69
b. n + (n + 1) = 69
c. n −(n + 1) = 69
d. n + 2n = 69

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option

he sells x mount because thats eqivilqant to the maz and then divided into quarters

step-by-step explanation: