A car is 500 feet behind a train. The train is traveling at a constant speed of 44 feet per second. If the car's speed could be modeled by the equation s(t)=4t^2, How long will it take for the car to catch up to the train. How many feet did the car travel before it caught up to the train?

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

y < -3

step-by-step explanation:

-3y - 2 > 7

-3y -2 + 2 > 7+2

-3y > 9

-3y/-3 < 9/-3   (change the inequality sign when multiplying or dividing by a negative number)

y < -3