Caleb has a four sided die, a six sided die, and a twelve sided die. He rolls the three dice and adds up the numbers showing. What is the expected value of the sum of the rolls

the expected value of the sum of the rolls is 12.5

Step-by-step explanation:

Given that

Caleb has 4 sided die, 6 sided die and 12 sided die

first we calculate the expected number of each of the dice

so Expected number for 4 sided die will be;

E(X1)4-sided = ( (1+2+3+4) / 4 ) = 2.5

E(X2)6-sided = ( (1+2+3+4+5+6) / 6 ) = 3.5

E(X3)12-sided = ( (1+2+3+4+5+6+7+8+9+10+11+12) / 12 ) = 6.5

so, the expected value of the sum of the roll will be

E(X) = ( E(X1) + E(X2) + E(X3)

E(X) = 2.5 + 3.5 + 6.5

E(X) = 12.5

Therefore,  the expected value of the sum of the rolls is 12.5

{3 + i, 3 - i, 3, -1}

step-by-step explanation:

b

step-by-step explanation:

it have 5 sides and 5 identicle angle.the rest does not have the same property as b.

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