Write the equation in slope-intercept form of a line with slope -2 that passes through the point (1.-7)

y=-2x-5

Step-by-step explanation:

y-y1=m(x-x1)

y-(-7)=-2(x-1)

y+7=-2x+2

y=-2x+2-7

y=-2x-5

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

3

step-by-step explanation:

because where the point where the 2 lines intersect is (3,-1) the x value is 3