Kari is comparing two numbers A and B, shown below. A = 600,705

B = 6,007,058

Which equation relates the two numbers?

(A)

A = 10B

(B)

A = 100B + 58

(C)

B = 10A + 8

(D)

B = 10A + 58

(E)

B = 100A + 8

Explanation:

This is something you would do through trial and error to check each answer choice

We can cross off A = 10B since

A = 10B = 10*(6,007,058) = 60,070,580

but that's not what A is actually equal to (it should be 600,705)

We can also cross off A = 100B + 58 because,

A = 100B + 58

A = 100*(6,007,058) + 58

A = 600,705,800 + 58

A = 600,705,858

But that doesn't match with A = 600,705 either

Now let's try the third equation

B = 10A + 8

B = 10(600,705) + 8

B = 6,007,050 + 8

B = 6,007,058

That matches with what your teacher gave you. So this confirms we have the correct equation.

I'll let you check the remaining two. You should find that they don't work out.

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752

step-by-step explanation:

assume that you have 3 different side lengths.   apply the pythagorean theorem here:   square each of the two shortest sides; call them a and b, so that their squares are a² and b².   also square the longest side, calling the result c².

now, if a² + b² = c² is true, the triangle is a right triangle; otherwise it is not a right triangle.