Choose the graph that solves this system of equations. y = 2x – 6
y = –4x + 3
Two lines that intersect at the origin. One line has a positive slope and the other has a negative slope. Two lines that intersect at about 2 comma negative one half. One line has a positive slope and the other has a negative slope. There is also a single dot at the origin. Two lines that intersect at about three halves comma negative 3. One line has a positive slope and the other has a negative slope. Two lines that both have a positive slope. They do not intersect on the part of the graph shown, but there is a single dot at the origin.

Two lines that intersect at about three halves comma negative 3. One line has a positive slope and the other has a negative slope.

Step-by-step explanation:

Given equations of line:

y = 2x – 6               ...(i)

y = –4x + 3            ...(ii)

On comparing with y=mx+c (slope-intercept form), where m= slope ,= y-intercept.

(i) has positive slope (2) and (ii) has negative slope(-4).

Eliminate (ii) from (i), we get

0 = 6x-9

⇒ 6x=9

⇒

Put value of x in (i), we get

Point of intersection = (three halves,  negative 3)

step-by-step explanation: h: (- 3, 6)

m: (1, - 2)

o: (7, 6)

r: (- 9, - 2)

midpoint of hm: (- 1, 2)

midpoint of or: (- 1, 2)

therefore, b is the midpoint of both diagonals bisect each other !

to prove the diagonals are perpendicular, show that the product of the slopes = - 1

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step-by-step explanation: