Write the equation of a line that is BOTH PARALLEL and PERPENDICULAR to
2x + 4y = 16 through ( 12,15)

Equation for the parallel line:
Equation for the perpendicular line:

Parallel line: y=-x+27

Perpendicular line: y=x+3

Step-by-step explanation:

y=mx+b, where m is the slope and b is the y-intercept.

Rearrange '2x+4y=16' to fit this format:

2x + 4y = 16

x+y=8

y=-x+8

Parallel line

If two lines are parallel, they have the same slope. So our equation goes from y=mx+b to y=-x+b. We know the line goes through (12,15), so we sub this in to get b:

15=-12+b

b=27

So our equation is y=-x+27

Perpendicular line

If two lines are perpendicular, the slope of one line is the negative inverse of another: eg, if a line had slope=3, the line perpendicular to it would have slope=-1/3. The negative inverse of -1 is 1, so our equation goes from y=mx+b to y=x+b.We know the line goes through (12,15), so we sub this in to get b:

15=12+b

b=3

So our equation is y=x+3

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation:

1^3 + 2^3 + 3^3 +4^3 = (1+2+3+4)^2

step-by-step explanation:

i am only able to answer the first part. i am not sure about the second part. sorry