Use quadrilateral ABCD with A(1, 5), B(2, 6), C(3, 3) and D(1, 3) and its transformation A'B'C'D' with A'(-3, 1), B'(0, 4), C'(3, -5) and D'(-3, -5). What is the scale factor of the transformation

The scale factor that transforms quadrilateral ABCD to quadrilateral A'B'C'D' is 3

Step-by-step explanation:

Quadrilateral ABCD has the following coordinates

A(1, 5), B(2, 6), C(3, 3) and D(1, 3)

The image A'B'C'D' has the following coordinates;

A'(-3, 1), B'(0, 4), C'(3, -5), D'(-3, -5)

The length of segment = √((2 - 1)² + (6 - 5)²) = √2

The length of segment = √((3 - 6)² + (3 - 2)²) = √10

The length of segment = √((1 - 3)² + (3 - 3)²) = 2

The length of segment = √((1 - 1)² + (3 - 5)²) = 2

For quadrilateral, we have;

A'(-3, 1), B'(0, 4), C'(3, -5), D'(-3, -5)

The length of segment =  √(0 - (-3))² + (4 - 1)²) = 3·√2

The length of segment = √((3 - 0)² + (-5 - 4)²) = 3·√10

The length of segment = √((-3) - 3)² + (-5 - (-5))²) = 6

The length of segment = √((-3) - (-3))² + ((-5) - 1)²) = 6

The scale factor that transforms quadrilateral ABCD to A'B'C'D' is given as follows;

Therefore, the scale factor that transforms quadrilateral ABCD to A'B'C'D' = 3

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

addition

step-by-step explanation: