An arrow is shot at 30.0° above the horizontal. Its velocity is 49 m/s, and it hits the target. What is the maximum height the arrow will attain?

30.625 m

Step-by-step explanation:

Maximum Height :

(u²sin²θ) / 2g

u = 49 m/s

θ = 30°

g = 9.8m/s

(49² * 0.5²) / 2 * 9.8

600.25 / 19.6

= 30.625 m

hello,

b) 62.47% of the students are between 14 and 18 years old.

step-by-step explanation:

mean = 15 and standard deviation = 2

student between 14 to 18

formula used z-score

for age 14 , z score

using z-table , p(z> -0.5)=0.3085

for age 18 , z score

using z-table , p(z< 1.5)=0.9332

p(-0.5< z< 1.5)=0.9332-0.3085 = 0.6247

thus, 62.47% of the students are between 14 and 18 years old.

click to let others know, how is it

0.0

0 votes

1

report

read more on -

step-by-step explanation:

2 liters for 10   people

step-by-step explanation: