The Kato family takes out a $30,000 home improvement loan. The loan has an annual interest rate of 6.5%. If the loan is paid back over 12 years instead of 10 years, how
much more interest will they pay?

$3900

Step-by-step explanation:

Given data

P= $30,000

r= 6.5%

t= 10 years

t= 12 years

Let us find the SI interest after 10 years

SI= PRT/100

SI= 30000*6.5*10/100

SI= 1950000/100

SI= 19500

Let us find the SI interest after 12 years

SI= PRT/100

SI= 30000*6.5*12/100

SI= 2340000/100

SI= 23400

The extra amount paid is

=23400- 19500

=$3900

step-by-step explanation:

a.   since the profit made in 2012 is equal to the profit made in 2014, the profit is           symmetric about the line y = 120,000.

step-by-step explanation:

given that megan owns a clothing boutique.

the profits of 2010, 11, are recorded and shown as follows:

years since     2010 0     1     2     3       4       5

profits made in 1000's   39       84     111     120   111     84

we find that profit gradually increases form 2010 to 2013 upto 120,   then starts decreasing.

the profits for 2012 and 2014 are the same while that of 2011 and 2015 are also the same.

this shows that there is symmetry about the line profit = 120000

hence answer is:

a.   since the profit made in 2012 is equal to the profit made in 2014, the profit is           symmetric about the line y = 120,000.

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r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option