T. Dr. Sox drives through two stoplights on her way to work. The first light is green
for 20 seconds out of each minute. The
second light is green for 35 seconds out
of each minute. What is the probability
that Dr. Sox will hit two green lights?

Question??

Dr. Sox drives through two stoplights on her way to work. The first light is green for 20 seconds out of each minute. The second light is green for 35 seconds out of each minute. What is the probability that Dr. Sox will hit two green lights?

Explanation;

Since this is an AND situation, we MULTIPLY the probabilities.

Answer/Explanation:

First light green:

P

1

=

20

60

=

1

3

Second light green:

P

2

=

35

60

=

7

12

Both lights green:

P

=

P

1

×

P

2

=

1

3

×

7

12

=

7

36

Of course, this is assuming that there is no "green wave" policy, or the two probabilities would not be independent

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet