In a large city, commuter trains are used to transport people into the downtown area. Trains arrive many times a day to a downtown station. While most are on time, some are late. The table shows on-time data from the past week. Train Status
On Time Late Total
Day of the Week Monday 32 8 40
Tuesday 24 16 40
Wednesday 37 3 40
Thursday 29 11 40
Friday 30 20 50
Total 152 58 210
What proportion of trains were late on Tuesday?

StartFraction 8 Over 40 EndFraction
StartFraction 58 Over 210 EndFraction
StartFraction 16 Over 40 EndFraction
StartFraction 24 Over 40 EndFraction

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

if a = 1,   and b = 2, then the answer is 47.99999999. if you round that to the nearest whole number, the answer is 48.

my computer is slow i can not see it sorry