Write an equation of the line that passes through the points (−6,20) and (0, 8).

y = -2x + 8

Step-by-step explanation:

(−6, 20) and (0, 8)

First you want to find the slope of the line that passes through these points. To find the slope of the line, we use the slope formula: (y₂ - y₁) / (x₂ - x₁)

Plug in these values:

(8 - 20) / (0 - (-6))

Simplify the parentheses.

= (-12) / (6)

Simplify the fraction.

-12/6

= -2

This is your slope. Plug this value into the standard slope-intercept equation of y = mx + b.

y = -2x + b

To find b, we want to plug in a value that we know is on this line: in this case, I will use the second point (0, 8). Plug in the x and y values into the x and y of the standard equation.

8 = -2(0) + b

To find b, multiply the slope and the input of x(0)

8 = 0 + b

b = 8

Plug this into your standard equation.

y = -2x + 8

This is your equation.

Check this by plugging in the other point you have not checked yet (-6, 20).

y = -2x + 8

20 = -2(-6) + 8

20 = 12 + 8

20 = 20

Your equation is correct.

Hope this helps!

answer: ouch. thats difficult

step-by-step explanation: