Determine the equation of the tangent to x− 3x +1 at the point (3,1)

9514 1404 393

  y = 3x -8

Step-by-step explanation:

We assume you want the tangent to the parabola y = x² -3x +1 at the given point. The slope is found using the derivative of the function at that point.

  y' = 2x -3

At x=3, the slope is ...

  y' = 2(3) -3 = 3

The equation of the line through point (3, 1) with a slope of 3 is ...

  y -1 = 3(x -3) . . . .  use the point-slope form of the equation for a line

  y = 3x -9 +1 . . . . . eliminate parentheses, add 1

  y = 3x -8

the answer would be 44.79

plz mark brainliest

step-by-step explanation:

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